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Update script no extracting values

Posted by Rufus Satekge 
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Update script no extracting values
April 23, 2013 02:33PM
Hi

My edit script is not extracting any value when I open it in the list script. The form pops up blank

Please Help
Language: PHP
//get value of id $player_id = $_GET[';player_id';]; //update data in database $query = "UPDATE playerinfo SET name = ';$name';, surname = ';$surname';, contactnumber = ';$contactnumber';, email = ';$email';, position = ';$position';, username = ';$username';, password = ';$password'; WHERE player_id = ';$player_id';"; //retrieve data from database $query = "SELECT * FROM playerinfo WHERE player_id = ';$player_id';"; $result = mysql_query($query) or die("Query failed: ".mysql_error());
avatar
Mac
Re: Update script no extracting values
April 23, 2013 03:11PM
This is not the list code.... your question does not make any sense.
Re: Update script no extracting values
April 25, 2013 01:11PM
Ok. Here is the list script
Language: PHP
$query = "SELECT * FROM playerinfo"; $result = mysql_query($query) or die("Query failed: ".mysql_error());   echo"<table border=';1';><tr bground=';#CCCCCC';><td>Name</td><td>Surname</td><td>Contact number</td><td>Email</td><td>Position</td><td>Username</td><td>Password</td><td colspan=';2';>Action</td></tr>"; while($row = mysql_fetch_array($result)) { $phone_id=$row[';player_id';]; echo"<tr><td>"; echo $row[';name';]; echo"</td><td>"; echo $row[';surname';]; echo"</td><td>"; echo $row[';contact number';]; echo"</td><td>"; echo $row[';email';]; echo"</td><td>"; echo $row[';position';]; echo"</td><td>"; echo $row[';username';]; echo"</td><td>"; echo $row[';password';]; echo"</td><td>"; echo"<a href=edit.php?player_id=$player_id&update=yes>Edit</a>"; echo"</td><td>"; echo"<a href=delete.php?player_id=$player_id&delete=yes>Delete</a>"; echo"</tr>"; } echo"</table>";
avatar Re: Update script no extracting values
April 25, 2013 01:17PM
Your first query will never be run.

$query is a variable that you assign a value to. First you assigned the value :
Language: PHP
$query = "UPDATE playerinfo SET name = ';$name';, surname = ';$surname';, contactnumber = ';$contactnumber';, etc...';";

and then you write this over that value:
Language: PHP
$query = "SELECT * FROM playerinfo WHERE player_id = ';$player_id';";

If you were to echo $query it would just show "SELECT * FROM playerinfo WHERE player_id = '$player_id". So go google how to run multiple queries on the same page. Hint: try moving different queries into different functions and have them return the result. smile

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avatar
Mac
Re: Update script no extracting values
April 25, 2013 02:15PM
If the 2nd line does not produce an error, then I have to ask a silly question - is the data in the table?

Language: PHP
//use this to see if there are rows with data given your query $num_rows = mysql_num_rows($result); echo "Number of rows: $num_rows";
Re: Update script no extracting values
April 29, 2013 02:08PM
Mac the problem is that when I click on the edit link in the list_players page, the edit form comes up empty as if there are no records the database.
And the echo statement output "Number of rows: 0. Question is why zero rows when there is data in the database
Language: PHP
//get value of id $player_id = $_GET[';player_id';];   //update data in database $query = "UPDATE playerinfo SET name = ';$name';, surname = ';$surname';, contactnumber = ';$contactnumber';, email = ';$email';, position = ';$position';, username = ';$username';, password = ';$password'; WHERE player_id = ';$player_id';"; //retrieve data from database $query = "SELECT * FROM playerinfo WHERE player_id = ';$player_id';"; $result = mysql_query($query) or die("Query failed: ".mysql_error()); $num = mysql_numrows($result); echo "Number of rows: $num"; $i = 0; while($i < $num){ $name = mysql_result($result,$i,"name"); $surname = mysql_result($result,$i,"surname"); $$contactnumber = mysql_result($result,$i,"contactnumber"); $email = mysql_result($result,$i,"email"); $position = mysql_result($result,$i,"position"); $username = mysql_result($result,$i,"username"); $password = mysql_result($result,$i,"password"); $i++;
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