Tut102 Exam Tut Q1. How do I determine d (TLU)

Hi

How do I determine d => the desired output before dong
the weight change calc.
Nowhere in notes it states when d should be 0 or when equals to 1.
Do when "gyppo" the system and let d be the opposite of f
(actual output). for example if f is 1 let d be 0 If f = 0 let d = 1
untill the weights do not change then you know that d is equal to f

REgards
Francois du Toit

Hi Francois,

To calculate the desired output d, you substitute the input vectors given with the the Boolean function f1 = x1 v x2x3

so <0 1 0> would mean

f1 = 0 v 1(0) = 0
there for the desired output for < 0 1 0 > would be 0.

Hope this helps ?

Hi Ronnie

Why 0 v 1(0)

Is it then 0 "and" 1(0) is the same
as o "and" 0 becuase 1(0) = 1*0 = 0
why the 2nd and third vector multiplied as 1(0)
why not
0 v 1 v 0 instead of
0 v 1(0)
Is the last zero multiplied the threshold vector?

Hi Ronnie

But the V is the disjunction meaning "OR"

I think it is like this

f1 = x1 v x2x3

For vectors
<o 1 o> ==> f1 = 0 v 1(0) = 0 v 0 ==> 0 not 0 like your one above?
<1 0 o> ==> f1 = 1 v 0(0) = 1 v 0 ==> 1 not 0 like your one above?
<0 0 1> ==> f1 = 0 v 0(1) = 0 v 0 ==> 1 not 0 like your one above?
<1 1 1> ==> f1 = 1 v 1(1) = 1 v 1 ==> 1 not 0 like your one above?


When trainig the function is
the s1,s2,s3 the x1,x2,x3??

So then the desired outcome is
s1 v s2(s3) for each x vector untill trained??

In the example in Tot501 and tut201

x1.~x2 = (s2+s3)~(s4s5)

So then from x1 vector till x13 vector
I use the x = (s1....s9) in the equation above
x1.~x2 = (s2+s3)~(s4s5)

So for each x1 till x13 I substitute the values
of s2,s3,s4,s5 in x1.~x2 = (s2+s3)~(s4s5)
to get d

What if we do not have the s1,s2,s3 equation is
s1 = x1, s2 = x2,s3= x3 ect..
The robot equation is as we know combination of s2,s3,s4,s5
becuase that is defined what if not defined we use the equation
in x's as the give us and substitute s's with x's
to get s1 v s2(s3)

Francois