Scope of my Variable

Ok not sure how to get this working...
x is at position 5 and it finds it correctly inside the loop but looses the value outside the loop...
my guess is its got to do with the variable scope...
but tried global and GLOBAL["Answer"]
and neither seems to work... any clues where I can look to find solution

Language: PHP
	               $string="this x is what I am looking for";
                 $Answer=strlen($string);
                $myAray = array("z","x","t");
		foreach($myAray as $Item){
 
		$ItemFind = strpos($string,$Item);
		echo $ItemFind ;
		//echo "window.alert($Answer)";
			if($Answer>$ItemFind){
				$Answer =$ItemFind;
				echo $Answer;
			}			
		}
		$Answer =$Answer+1;
		echo $Answer

Is this for the array assignment page?

Hey Marius.
Good to see you also taking this

Nope this is a string function I am trying to get right....
the function works fine...
the array and the loop works fine. (you can see this by looking at the echo inside the loop)

but the echo after the loop for some reason makes the $Answer 0 (+1)
my best guess is the scope of the variable... but checked the net and tried a few things but nothing as of yet...

I will keep going though.
(I prob asked to quick and should bash my head a little more first )

From the top of my head - foreach does not have scope - it will exist outside. The problem is

Language: PHP
if($Answer>$ItemFind){

It exists in a loop, so it runs through the other conditions as well, and is set to zero when it is not larger. Remove the if statement - you can use it outside.

Thanks Mac I will go try it...

I think I need the if statement in the loop to change my Answer...
the goal is to find the first vowel in a string so if it is only after the loop....
I think it wont be checking all the vowels...

Hmmm... but that said I "THINK" I just clicked what you mean...
when the vowel is not found then the $ItemFind is set to 0 and then it will def be < $Answer....

(Sorry to say but if that is the case that is really bad logic from people that wrote that string function.... should rather return Null or False....what hapens if there is a vowel in position 0.....i.e $String = "Emerald"
(Hahaha.... sorry have to laugh at myself trying to critisizing people thats so smart they developed a programming language.... I might be getting over confident with the little knowledge that I have )
well guess I will go play around with the code when I get home.

Ok thanks for that

Yes, not all code is good. My suggestion is perhaps not the best either.... but as this query falls outside the course, I stop here....!

holy moses...I got it...damn so stupid I could just roll over and give up on life...
ok maybe that is a bit too dramatic...

was a double prob...
firstly i added this

Language: PHP
if(strpos($string,$leter)!=false){
}

to make sure it only ran the original if statement if it has found a particular vowel
secondy (I did not include all my code and another problem was when trying to add text and an int.....
like so

Language: PHP
$Answer = "The first leter is seen in position: ".$Answer +1;

it totally freaked out and always only returned one...why...well not 100% sure
but by changing it to

Language: PHP
$Answer = "The first leter from list is seen in position: ".($Answer +1);

it worked

Also:
if the leter is siting at position 1 then the strpos returns 0 and 0 in an if statement returns false
so it never steps into the other if statment to update the
had to hack it by adding a leter to front of $string
sorry for wasting anyones time but thanks for trying to help.

@42609852 I see you got your problem solved, well done.