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Jan/Feb 2007 Paper Q5 a(ii)

Posted by gert_yes

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gert_yes

Jan/Feb 2007 Paper Q5 a(ii)
November 14, 2007 05:35PM

Registered: 17 years ago
Posts: 94
Rating: 0

Hi All,

Any one get what is to happen here.

Liebmann is a repetitive calculation of the same grid point values basically getting an average of the four surrounding grid points, until tollerance is met.

Any one get the rewriting of the difference equation into iterative formula as asked in that question? (Jan/Feb 2007 Paper Q5 a(ii)).

Thanks,

Gert.

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lycium

Re: Jan/Feb 2007 Paper Q5 a(ii)
November 15, 2007 02:13AM

Registered: 17 years ago
Posts: 2,813
Rating: 0

on 2nd thought after my email reply to you, maybe they just want (^ means superscript, not exponent, and _ means subscript)

u^(k+1) = (u^k_left + u^k_right + u^k_above + u^k_below) / 4

to show how the k+1th values are obtained from the k-th ones.